| 281 |
A firm wants ₹1,00,000 at the end of 5 years. Interest is 10% compounded annually. Approximately how much mus… |
Mathematics/Applied Mathematics
Perpetuity and sinking funds |
Hard |
| 282 |
A loan carries interest at 12% per annum compounded monthly. The value of i to be used in the EMI formula is: |
Mathematics/Applied Mathematics
EMI |
Easy |
| 283 |
For a loan repaid by EMIs on the reducing-balance method, which statement about the instalments over time is … |
Mathematics/Applied Mathematics
EMI |
Medium |
| 284 |
A loan of ₹60,000 is taken at a flat rate of 10% per annum for 2 years and repaid in equal monthly instalment… |
Mathematics/Applied Mathematics
EMI |
Medium |
| 285 |
Using the reducing-balance method, the EMI on a loan of ₹1,00,000 at 12% per annum for 12 months is approxima… |
Mathematics/Applied Mathematics
EMI |
Easy |
| 286 |
A loan of ₹20,000 at 1% per month is repaid in 2 equal monthly instalments (reducing balance). Each instalmen… |
Mathematics/Applied Mathematics
EMI |
Hard |
| 287 |
An investment of ₹50,000 is worth ₹60,000 at the end of the period, with no other income. The nominal rate of… |
Mathematics/Applied Mathematics
Rate of return and CAGR |
Easy |
| 288 |
The compound annual growth rate of an investment assumes that: |
Mathematics/Applied Mathematics
Rate of return and CAGR |
Easy |
| 289 |
An investment of ₹10,000 grows to ₹14,641 in 4 years. Its CAGR is: |
Mathematics/Applied Mathematics
Rate of return and CAGR |
Medium |
| 290 |
A share is bought for ₹200, pays a dividend of ₹10 during the year and is sold for ₹230 at the end of the yea… |
Mathematics/Applied Mathematics
Rate of return and CAGR |
Medium |
| 291 |
An investment rises by 50% in the first year and falls by 50% in the second year. Its CAGR over the two years… |
Mathematics/Applied Mathematics
Rate of return and CAGR |
Hard |
| 292 |
A machine costs ₹50,000, has a residual value of ₹5,000 and a useful life of 9 years. The annual depreciation… |
Mathematics/Applied Mathematics
Linear depreciation |
Easy |
| 293 |
For the machine costing ₹50,000 with annual straight-line depreciation of ₹5,000, the book value at the end o… |
Mathematics/Applied Mathematics
Linear depreciation |
Easy |
| 294 |
An asset costing ₹50,000 is depreciated by ₹5,000 each year on the straight-line method. The rate of deprecia… |
Mathematics/Applied Mathematics
Linear depreciation |
Medium |
| 295 |
A vehicle costs ₹1,20,000 and has a residual value of ₹20,000. If the straight-line depreciation is ₹12,500 p… |
Mathematics/Applied Mathematics
Linear depreciation |
Medium |
| 296 |
A machine is bought for ₹80,000 and ₹5,000 is spent on installation. Its residual value after 10 years is ₹5,… |
Mathematics/Applied Mathematics
Linear depreciation |
Hard |
| 297 |
A bond has a face value of ₹1,000 and an annual coupon rate of 8%. The annual coupon payment is: |
Mathematics/Applied Mathematics
Bond valuation |
Easy |
| 298 |
A bond's coupon rate is exactly equal to the market rate of interest on similar bonds. The bond will sell: |
Mathematics/Applied Mathematics
Bond valuation |
Easy |
| 299 |
If market interest rates rise after a fixed-coupon bond is issued, the price of that bond will: |
Mathematics/Applied Mathematics
Bond valuation |
Medium |
| 300 |
A 2-year bond with face value ₹1,000 pays a 10% annual coupon. If the market yield is 8%, its value is approx… |
Mathematics/Applied Mathematics
Bond valuation |
Medium |